From: MonkeeSage <MonkeeSage@...>
Date: 2007-12-06T03:55:00+09:00
Subject: Re: Ruby equivalent for `du`

On Dec 5, 11:53 am, Christian von Kleist <cvonkle...@gmail.com> wrote:
> On Dec 5, 2007 12:10 PM, MonkeeSage <MonkeeS...@gmail.com> wrote:
>
>
>
>
>
> > On Dec 5, 10:51 am, Christian von Kleist <cvonkle...@gmail.com> wrote:
> > > I wrote a simple method for recursively finding the size of a
> > > directory, because I didn't see anything in File::Stat or FileUtils
> > > that does that.  Am I missing it?  Does Ruby already have an
> > > equivalent to `du`?
>
> > >   def size(f)
> > >     return File.size(f) unless File.directory?(f)
> > >     Dir.entries(f)[2..-1].inject(0) {|total, s| total + size(File.join(f, s))}
> > >   end
>
> > Couple problems with that approach 1.) assuming that ".", ".." are the
> > first elements of the entries array, 2.) for deep directories you'll
> > run out of stack very quickly. Have a look at the example at the top
> > of the Find module. ;)
>
> > [1]http://www.ruby-doc.org/core/classes/Find.html
>
> > Regards,
> > Jordan
>
> Good point!  Something like %w(. ..).include?(file) would be better
> than relying on . and .. to be the first two entries.  I'm not worried
> about stack space, though I did consider it.  For this application I
> won't find thousands of levels of subdirectories, and even then I
> probably wouldn't run out of stack space.  I could rewrite the
> recursion as a loop, but...
>
> As you suggested, I should have used Find.find instead.  The
> implementation is simpler, more readable, and more robust:
>
> require 'find'
> def size(f)
>   total = 0
>   Find.find(f) {|s| total += File.directory?(s) ? 0 : File.size(s)}
>   total
> end
>
> (For my application I don't care about the size of directories since
> those are highly configuration dependent and this script must produce
> the same result with the same file/directory tree on different
> computers.)
>
> Thanks, Jordan!

No problem. :)

Regards,
Jordan