From: Christian <chippersbox@...>
Date: 2007-11-28T13:43:24+09:00
Subject: Re: Binary Logic, Bug or Feature?

It should work if you use && instead of and. Not sure why that is, but
I'm experencing the same thing as you when doing x = true and false,
but it works as expected when using x = true && false.


On 11/28/07, Malcolm Lockyer <maxpenguin@gmail.com> wrote:
> Hi Guys,
>
>
> I have been pulling my hair out for the last 20 minutes trying to find
> out what is wrong in my app that has some pretty basic binary logic.
> Here is a concise example in an irb session that shows my problem
> (certainly, what I was working on wasn't nearly as simple the sides of
> AND were variables etc.):
>
> ?> x = true and true
> => true
> >> x
> => true
>
> (this is what I expect, true and true = true)
>
> >> x = true and false
> => false
> >> x
> => true
>
> But what I've got here is "true and false" == false, but it assigns
> true to x. So true and false == false, but really == true... Have I
> lost my mind, should it do this? Does it do it for anyone else? It
> seems weird to me since the first example does what I expect, but the
> second doesn't...
>
> So now I'm reduced to doing something like:
> if (true and false) then x = true else x = false end
> which is kind of annoying, and not very ruby-esque IMO.
>
> Any advice appreciated!
>
> $ ruby -v
> ruby 1.8.5 (2006-08-25) [i486-linux]
>
> OS is Ubuntu 7.04.
>
> (I know, old ruby ver - its just the stock ubuntu one)
>
>
> THANKS!
> - Malcolm.
>
>


-- 

"Every child has many wishes. Some include a wallet, two chicks and a
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