From: Phrogz <phrogz@...>
Date: 2007-11-27T23:10:00+09:00
Subject: Re: Most elegant way to do this?

On Nov 27, 2:06 am, Robert Klemme <shortcut...@googlemail.com> wrote:
> 2007/11/27, Phrogz <phr...@mac.com>:
>
> > You missed the +1 needed to take rand(5) to 1..6 instead of 0..5.
>
> And everybody apparently missed 6 because rand(5) will yield *5*
> values ranging in 0..4. :-))

Oh crimeny...oops. :p


> There is another one, that - at least theoretically - saves some
> addition efforts:
>
> require 'enumerator'
>
> def roll(number)
>   raise ArgumentError, "Negative!" if number < 0
>   number.to_enum(:times).inject(number) {|s,| s + rand(6)}
> end

You know, I _want_ to embrace to_enum, because it's certainly
excellently powerful and abstract...but somehow I just don't grok it.
Thanks for the reminder. Sometime I'll have to think about it.

(I wish I could find some flaw with it, and say "no no no, what it
really should be is ____"; I just somehow basically find it confusing.)