From: mengx@...
Date: 2001-12-10T23:01:57+09:00
Subject: [ruby-talk:28082] Re: How does puts decide how to print a given object?

(If I understood this thread correctly)
in the case of a = nil
a.to_s  ==> ""
a.inspect  ==> nil

so puts actually calls inspect for output, at least for this one, correct?



> "puts a" does
> 
>   if a is an array
>     puts each element of it
>   else
>     a = a.to_s
>     print a
>     print "\n" unless a[-1] == ?\n
>   end
> 
> Use print for simpler behavior.
> 
> 							matz.
>