From: Greg Weeks <greg.weeks@...>
Date: 2007-11-16T19:01:39+09:00
Subject: Re: "&prock", not "&block"

Eric Hodel wrote:
> > It may be that "&foo" is pedagogically described as the "foo"  
> > parameter with an "&" modifier.  But that is misleading.
> 
> This is correct, and this is what happens.  Its not misleading.

I take your point.  Thanks for the correction.

Nevertheless, even though the argument is a block, the parameter foo is
not.  If you want to use the *block* argument in the method body, you
use the expression &foo, not foo.  foo is a proc; &foo -- an expression,
not a parameter as I erroneously said -- is a block.

> def z(&foo)
>    p foo
> end
> 
> z() # => nil

Because no block was supplied.
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