From: "Benjamin M. A'Lee" <bma+lists@...>
Date: 2007-11-16T07:16:33+09:00
Subject: Re: Using a variable with gsub & sub

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On Fri, Nov 16, 2007 at 06:34:16AM +0900, Peter Vanderhaden wrote:
> In the following statement, I'm replacing ,, with ,NULL,.
>=20
> $inrec =3D $inrec.sub(',,\\',',NULL,')
>=20
> What I want to do is something like this:
>=20
> $inrec =3D $inrec.sub(',,\\',',$variable,')
>=20
> Unfortunately, I haven't been able to figure out the syntax for using a
> variable with sub & gsub.  Can someone help me out?
> Thanks.

The replacement is simply a string, so you could do:

	$inrec =3D $inrec.sub(',,\\',','+$variable+',')

or

	$inrec =3D $inrec.sub(',,\\',',#{$variable},')

--=20
Benjamin A'Lee :: benjamin.alee@subvert.org.uk
Subvert Technologies :: http://subvert.org.uk/

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