From: Rick DeNatale <rick.denatale@...>
Date: 2007-11-11T23:59:06+09:00
Subject: Re: The Man or Boy Recursion Test

On Nov 11, 2007 9:21 AM, Tim Hunter <TimHunter@nc.rr.com> wrote:
>
> I realized last night that the ||= is superfluous. A simple assignment
> is enough.
>
> b = Proc.new { k -= 1; a(k, b, x1, x2, x3, x4) }

Right, because b will always be nil here, it's a local variable so
there's a new b for each resursion.  Otherwise it would kind of defeat
what the Man Or Boy example is trying to illustrate.

And it can be made a little shorter, and more computer sciency <G>, by
replacing all those "Proc.new"s with "lambda"s.

# Man or boy test
def a(k, x1, x2, x3, x4, x5)
  b = lambda { k -= 1; a(k, b, x1, x2, x3, x4) }
  return k <= 0 ? x4[] + x5[] : b[]
end

puts a(10, lambda {1}, lambda {-1}, lambda {-1}, lambda {1}, lambda {0})


-- 
Rick DeNatale

My blog on Ruby
http://talklikeaduck.denhaven2.com/