From: Konrad Meyer <konrad@...>
Date: 2007-10-31T03:27:46+09:00
Subject: Re: RUBY DRY to replace 6 lines in 1

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Quoth Josselin:
> I have a group of lines  (used in Googlemaps display)  based on 2 arrays :
>=20
> zl =3D 9 if farthest_proposition.distance_to(origin) < =3D 25.0
> zl =3D 10 if farthest_proposition.distance_to(origin) <=3D 15.0
> zl =3D 11 if farthest_proposition.distance_to(origin) <=3D 10.0
> zl =3D 12 if farthest_proposition.distance_to(origin) <=3D 5.0
> zl =3D 13 if farthest_proposition.distance_to(origin) < =3D2.0
> zl =3D 14 if farthest_proposition.distance_to(origin) <=3D 1.0
>=20
> how could I replace it the dryest way possible ?
>=20
> zl =3D [9, 10, 11, 12, 13, 14]
> distance =3D [1.0, 2.0, 5.0, 10.0, 15.0, 25.0]
> farthest_proposition.distance_to(origin) is never > 25 (eliminated before=
=2E.)
> farthest_proposition.distance_to(origin)  can be 0.0, never negative
>=20
> thanks for yoru suggestions...
>=20
> joss

  zl =3D case farthest_proposition.distance_to(origin)
    when 0..1
      14
    when 1..2
      13
    when 2..5
      12
    when 5..10
      11
    when 10..15
      10
    when 15..25
      9
  end

HTH,
=2D-=20
Konrad Meyer <konrad@tylerc.org> http://konrad.sobertillnoon.com/

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