From: Sebastian Probst Eide <sebastian.probst.eide@...>
Date: 2007-10-31T02:41:01+09:00
Subject: Re: RUBY DRY to replace 6 lines in 1

Couldn't you write something like this?

def	get_zl(origin)
	temp_val = farthest_proposition.distance_to(origin)
   	[{:value=>1.0, :zl=>14}, {:value=>2.0, :zl=>13},  
{:value=>5.0, :zl=>12}, {:value=>10.0, :zl=>11},  
{:value=>15.0, :zl=>10}, {:value=>25.0, :zl=>9}].each {|pair| return  
pair[:zl] if temp_val <= pair[:value]}
end

Maybe it is not the smartest way to solve the problem, but it is a  
different solution none the less. Hope it helps and let's you find  
the ultimate solution yourself!
I didn't replace it with one line as you requested, but with four...


Best regards
Sebastian

On 30. okt. 2007, at 13.50, Josselin wrote:

> I have a group of lines  (used in Googlemaps display)  based on 2  
> arrays :
>
> zl = 9 if farthest_proposition.distance_to(origin) < = 25.0
> zl = 10 if farthest_proposition.distance_to(origin) <= 15.0
> zl = 11 if farthest_proposition.distance_to(origin) <= 10.0
> zl = 12 if farthest_proposition.distance_to(origin) <= 5.0
> zl = 13 if farthest_proposition.distance_to(origin) < =2.0
> zl = 14 if farthest_proposition.distance_to(origin) <= 1.0
>
> how could I replace it the dryest way possible ?
>
> zl = [9, 10, 11, 12, 13, 14]
> distance = [1.0, 2.0, 5.0, 10.0, 15.0, 25.0]
> farthest_proposition.distance_to(origin) is never > 25 (eliminated  
> before..)
> farthest_proposition.distance_to(origin)  can be 0.0, never negative
>
> thanks for yoru suggestions...
>
> joss
>
>