From: Peter Roome <pete.roome@...>
Date: 2007-10-27T04:51:51+09:00
Subject: Re: Rounding to the nearest 0.05

> Just off-hand, my initial reaction would be:
> 
>   (a * 20).round.to_f/20
> 
> where "a" is your variable.  Some quick tests with irb seems to show
> this as working.
> 
> Coey

Cheers for the quick response guys, much appreciated. What difference
would the .to_f make between these solutions?
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