From: mortee <mortee.lists@...>
Date: 2007-10-12T19:43:12+09:00
Subject: Re: Ignore printout

Fredrik wrote:
> I am still confused over why STDOUT is not a constant though...
> Thanks for your pointers!

I'd guess that when you reopen a stream, then it as an object remains
the same, just what you send it will end up somewhere else than before.
In contrast, when you assign to a variable, the object itself changes
which that variable references.

Since $stdout and STDOUT initially point to the same object, if you dont
assign $stdout, instead you modify the onject itself, the two continue
to reference the same original object. Remember that you can modify a
constant object's state without any warning anyway, so you could even
reopen STDOUT itself.

mortee