From: "Jesús Gabriel y Galán" <jgabrielygalan@...>
Date: 2007-10-08T21:25:27+09:00
Subject: Re: regexp question - look for parentheses then remove them

On 10/8/07, Max Williams <toastkid.williams@gmail.com> wrote:
> I'm struggling with a regular expression problem, can anyone help?
>
> I want to take a string, look for anything in parentheses, and if i find
> anything, put it into an array, minus the parentheses.
>
> currently i'm doing this:
>
> parentheses = /\(.*\)/
> array = string.scan(parentheses)
>
> This gives me eg
>
> "3 * (1 + 2)" => ["(1 + 2)"]
>
>  - but is there an easy way to strip the parentheses off before putting
> it into the array?
>
> eg
> "3 * (1 + 2)" => ["1 + 2"]
>
> In addition, if i have nested parentheses inside the outer parentheses,
> i want to keep them, eg
>
> "3 * (1 + (4 / 2))" => ["1 + (4 / 2)"]
>
> can anyone show me how to do this?

x = "3 * (1 + 2)".match(/\((.*)\)/)
x.captures
=> ["1 + 2"]
x = "3 * (2 + (1 + 3))".match(/\((.*)\)/)
x.captures
=> ["2 + (1 + 3)"]

Hope this helps,

Jesus.