From: brabuhr@...
Date: 2007-10-02T22:35:40+09:00
Subject: Re: a = b = c order of evaluation weird

On 10/2/07, SpringFlowers AutumnMoon <summercoolness@gmail.com> wrote:
>
>   a = Array(1..100)
>
>   a[0..a.size/2] = a[a.size*2/3..-1] = nil
>
> won't work and requires
>
> why is that?

a = Array(1..100)
a[0..a.size/2] = a[a.size*2/3..-1] = nil
p a

a = Array(1..100)

a.[]=(
  0..(a.size)./(2),
  a.[]=(
    (((a.size).*(2))./(3))..-1, nil
  )
)

p a