From: Morton Goldberg <m_goldberg@...>
Date: 2007-09-01T02:39:42+09:00
Subject: Re: Dispatching when function name is stated as a symbol

On Aug 31, 2007, at 4:48 AM, Ronald Fischer wrote:

>>> Hence, if
>>>   x=cb.call
>>> causes x to contain [:g2, 25, 'dummy'], I would like to execute
>>>   g2(25,'dummy')
>>>
>>> I have not found a convincing way of doing this.
>>
>> Would this work for you?
>>
>> def f(&cb)
>> 	x=cb.call
>> 	name = x[0]
>> 	args = x[1..-1]
>> 	send(name, *args);
>> end

It can made even simpler:

def f(&cb)
    send(*cb.call)
end

def g1(a,b,c)
    puts "g1: #{a}, #{b}, #{c}"
end

def g2(d,e)
    puts "g2: #{d}, #{e}"
end

f { [:g1, 1, 2, 3] } # >> g1: 1, 2, 3
f { [:g2, 2, 3] }    # >> g2: 2, 3

Regards, Morton