From: grocery_stocker <cdalten@...>
Date: 2007-08-30T09:25:14+09:00
Subject: How does ruby handle scope and closure in this case?

How come when I do something like

#!/usr/bin/ruby -w

def n_times(thing)
        return thing
end

pi = n_times(23);
puts pi


the variable 'thing' doesn't go out of scope.

But when I do something like

#!/usr/bin/ruby

def n_times(thing)
        return lambda{|n| thing * n}
end

pi = n_times(23);
puts pi.call(2)


The varialble 'thing' does go out of scope.