From: Robert Klemme Date: 2007-08-24T22:52:15+09:00 Subject: Re: Combining Array Elements 2007/8/24, Yossef Mendelssohn : > On Aug 24, 7:50 am, gregarican wrote: > > I have an array that I would like to combine elements. Here's a sample > > array: > > > > [["Value A", "Value B", 3], ["Value A", "Value C", 2],["Value A", > > Value B", 1]] > > > > What I would like to do is find the elements where the first two items > > are the same and then combine the third. The resulting array would > > consist of: > > > > [["Value A", "Value B", 4],["Value A", "Value C", 2]] > > > > This is something that is out in left field in terms of how I've used > > arrays in the past. Anyone know of a quick bit of script I can whip up > > that will suit the task? > > > irb(main):001:0> orig_array = [["Value A", "Value B", 3], ["Value A", > "Value C", 2],["Value A", "Value B", 1]] > => [["Value A", "Value B", 3], ["Value A", "Value C", 2], ["Value A", > "Value B", 1]] > irb(main):002:0> hash = Hash.new(0) > => {} > irb(main):003:0> orig_array.each { |elem| hash[ elem[0,2] ] += > elem[2] } > => [["Value A", "Value B", 3], ["Value A", "Value C", 2], ["Value A", > "Value B", 1]] > irb(main):004:0> hash.collect { |k, v| k + [v] } > => [["Value A", "Value C", 2], ["Value A", "Value B", 4]] > > > or, more concisely > > > irb(main):001:0> orig_array = [["Value A", "Value B", 3], ["Value A", > "Value C", 2],["Value A", "Value B", 1]] > => [["Value A", "Value B", 3], ["Value A", "Value C", 2], ["Value A", > "Value B", 1]] > irb(main):002:0> orig_array.inject(Hash.new(0)) { |hash, elem| > hash[ elem[0,2] ] += elem[2]; hash }.collect { |k, v| k + [v] } > => [["Value A", "Value C", 2], ["Value A", "Value B", 4]] I believe there is an even simpler solution: irb(main):001:0> arr=[["Value A", "Value B", 3], ["Value A", "Value C", 2], ["Value A", "Value B", 1]] => [["Value A", "Value B", 3], ["Value A", "Value C", 2], ["Value A", "Value B", 1]] irb(main):003:0> arr.inject(Hash.new(0)) {|ha,(a,b,c)| ha[[a,b]]+=c;ha} => {["Value A", "Value C"]=>2, ["Value A", "Value B"]=>4} irb(main):004:0> arr.inject(Hash.new(0)) {|ha,(a,b,c)| ha[[a,b]]+=c;ha}.inject([]) {|re,v| re< [["Value A", "Value C", 2], ["Value A", "Value B", 4]] Of course, the most elegant solution uses #inject - in this case two injects. :-) Although, this one might be even better: irb(main):007:0> arr.inject(Hash.new(0)) {|ha,(a,b,c)| ha[[a,b]]+=c;ha}.map {|x| x.flatten} => [["Value A", "Value C", 2], ["Value A", "Value B", 4]] At least 1 #inject. :-) Kind regards robert