From: cliveharber@...
Date: 2007-08-24T17:42:51+09:00
Subject: Re: subarray using [1,-1] returns nil.

Hi Todd

The operation b = a[1,-1] is a slice operation where the first index is the start point and the second is the length of the array that you are retrieving - this is why you are getting nil for 'b' - the way to do this would be to use an inclusive range like this b = a[1..-1] - this will return the results that you expect.

---- Todd Burch <promos@burchwoodusa.com> wrote: 
> a = %w(a b c d e f g) ;
> puts "a.length = #{a.length}" ;
> 
> b = a[1,-1] ;
> puts "b.length = #{b.length}" ;
> 
> Why is array b nil after the subarray?  I expect it to be equal to "a"
> minus the first element.
> 
> Todd
> -- 
> Posted via http://www.ruby-forum.com/.
>