From: david karapetyan <dkarapetyan@...>
Date: 2007-08-18T17:42:15+09:00
Subject: Re: method access to the enclosing method's locals?

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Ok, just ignore all my previous posts. I should have done some more research
before I started typing. This code will actually work.

def go2(arg)
  (class << self; self; end).class_eval do
    define_method(:hi) do puts "Hi #{arg}" end
  end
end

Once you call go2 with some argument it will create the method hi that will
have access to any argument passed to go2. I have to say though all the
redirection with the singleton class makes my head spin a little.

On 8/17/07, Larry Kluger <rubyforum@kluger.com> wrote:
>
>
> Hi,
>
> How can a method gain access to the enclosing method's locals?
>
> def go2(arg)
>   def hi
>     puts "Hi #{arg}!"
>   end
>
>   a={:h => :hi}
>   send(a[:h])
> end
>
> go2 'Larry' ==>> NameError: undefined local variable or method `arg' for
> main:Object
>
> In go2, is there a clean way for the hi method to have access to the
> arg local?
>
> Thanks!
>
> Larry
> --
> Posted via http://www.ruby-forum.com/.
>
>

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