From: david karapetyan <dkarapetyan@...>
Date: 2007-08-18T16:29:07+09:00
Subject: Re: method access to the enclosing method's locals?

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Here's one way. First define the closure then use define_method to turn the
closure into an actual method.

def go2(arg)
  closure = proc { puts "Hi #{arg}" }
  define_method(:hi,closure)
end

I haven't tested the above code so I'm not sure if it really works.

On 8/18/07, david karapetyan <dkarapetyan@gmail.com> wrote:
>
> The general concept involved is that of a closure and it is certainly
> possible to define closures in ruby and at some point or another someone
> pointed out a way of turning closures into methods I don't remember how
> though.
>
> On 8/17/07, Larry Kluger <rubyforum@kluger.com> wrote:
> >
> >
> > Hi,
> >
> > How can a method gain access to the enclosing method's locals?
> >
> > def go2(arg)
> >   def hi
> >     puts "Hi #{arg}!"
> >   end
> >
> >   a={:h => :hi}
> >   send(a[:h])
> > end
> >
> > go2 'Larry' ==>> NameError: undefined local variable or method `arg' for
> >
> > main:Object
> >
> > In go2, is there a clean way for the hi method to have access to the
> > arg local?
> >
> > Thanks!
> >
> > Larry
> > --
> > Posted via http://www.ruby-forum.com/ .
> >
> >
>

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