From: Phrogz <phrogz@...>
Date: 2007-08-17T13:45:00+09:00
Subject: Re: Passing two functions as parameters

On Aug 16, 8:00 pm, Pe�a, Botp <b...@delmonte-phil.com> wrote:
> [mailto:list-bou...@example.com] On Behalf Of Frank Meyer
> i like ruby since it treats vars and methods alike.
>
> this is just a simple example,
>
> irb(main):001:0> def x
> irb(main):002:1>   puts "x"
> irb(main):003:1> end
> => nil
> irb(main):004:0> def y
> irb(main):005:1>   puts "y"
> irb(main):006:1> end
> => nil
> irb(main):012:0> def test2(a=x,b=y,c=x)
> irb(main):013:1>   a
> irb(main):014:1>   b
> irb(main):015:1>   c
> irb(main):016:1> end
> => nil
> irb(main):017:0> test2
> x
> y
> x
> => nil

You may not realize it, but what you just wrote is the same as:
def test2( a=x, b=y, c=x )
  nil
  nil
  nil
end

The methods are being invoked as the method parameters are being set
up, and three nil values (the return value of those methods, which is
the return value of their 'puts' calls) are being assigned to your
variable. I only point this out since the code sort of implies that
the parameter assignments are treating methods as first-class
functions, and you are invoking them inside the method.