From: Simon Schuster <significants@...>
Date: 2007-08-16T14:21:22+09:00
Subject: Re: excessively verbose request for help with regex and arrays

yes, this helps a lot! I should have assumed that parsing the time
would enable arithmetic like Fri - Thurs, instead I assumed I'd have
to put it all to integers.

I will have to think over more of exactly what I'm trying to do with
the arrays/hashes, after I read more about hashes, I think. thanks!

On 8/15/07, Alex Gutteridge <alexg@kuicr.kyoto-u.ac.jp> wrote:
> On 16 Aug 2007, at 13:46, Simon Schuster wrote:
>
> > thanks, but since the time is only going to be used for arithmetic
> > parsing it for additional information isn't helpful, and the roll-over
> > will be problematic.
> >
> > (23:54:45) - (00:03:45) != 00:09:00
>
> Does this help?
>
> Parse the two dates like Eric suggested. If the second (later) time
> is less than the first then add a day to it (60*60*24 seconds). Then
> subtract one from the other to get the difference in seconds.
>
> irb(main):023:0> t1 = Time.parse('23:54:45')
> => Thu Aug 16 23:54:45 +0900 2007
> irb(main):024:0> t2 = Time.parse('00:03:45')
> => Thu Aug 16 00:03:45 +0900 2007
> irb(main):025:0> t2 += (60 * 60 * 24) if t2 < t1
> => Fri Aug 17 00:03:45 +0900 2007
> irb(main):026:0> diff = t2 - t1
> => 540.0
>
> Alex Gutteridge
>
> Bioinformatics Center
> Kyoto University
>
>
>
>