From: Logan Capaldo <logancapaldo@...>
Date: 2007-08-12T20:27:31+09:00
Subject: Re: Split a string based on change of character

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On 8/12/07, Simon Kr=F6ger <SimonKroeger@gmx.de> wrote:
>
> Pe=F1a schrieb:
> > From: William James [mailto:w_a_x_man@yahoo.com]
> > # s =3D "ZBBBCZZ"
> > #     =3D=3D>"ZBBBCZZ"
> > # s.scan( /((.)\2*)/ ).transpose.first
> > #     =3D=3D>["Z", "BBB", "C", "ZZ"]
> > # s.gsub( /(.)(?!\1)/, "\\1\n" ).split
> > #     =3D=3D>["Z", "BBB", "C", "ZZ"]
> >
> > ruby hacker, James, that is cool! gotta keep this.
> > kind regards -botp
>
> Yeah, nice!
>
> i think one can simplify from
>
> s.gsub( /(.)(?!\1)/, "\\1\n" ).split
>
> to
>
> s.gsub(/(.)\1*/, '\0 ').split
>

Yes it appears so.  Another variation  would be (this lets you use the
method on strings that contain whitespace already correctly):
require 'enumerator'
s.enum_for(:gsub, /(.)\1*/).to_a

Which is sort of back to the original scan method.

?
>
> cheers
>
> Simon
>
>
>

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