From: dblack@...
Date: 2007-08-08T23:27:34+09:00
Subject: Re: case statement

Hi --

On Wed, 8 Aug 2007, Alex Young wrote:

> Shai Rosenfeld wrote:
>> Alex Young wrote:
>>> Shai Rosenfeld wrote:
>>>> end
>>>> 
>>>> ((i.e, whatever value is included in the array))
>>>> ...how do i do this?
>>> Does the Array#include? method do what you need?  Perhaps a more
>>> fleshed-out example might help?
>> 
>> Array#include is EXACTLY what i need, but syntaxtetically (if u get the 
>> drift) i'm not sure how to do it:
>> 
>> case [3, 45, 6, 'abc'].inlcude?
>> when 1: 'no good'
>> when 3: 'good!'
>> when 'lolo': 'no good'
>> end
> I'm not sure why you're using case here.  I'd do it like this:
>
> [3, 45, 6, 'abc'].include?(var) ? "good" : "no good"

I think the problem is that if it includes both 1 and 3, it's no good.

You (Shai) could do something like:

module YesNo
   def yes_no(a,b)
     [*a].all? {|e| include?(a) } and not [*b].any? {|e| include?(e) }
   end
end

a = [1,2,3,4,5]
a.extend(YesNo)

p a.yes_no(3,6)    # true
p a.yes_no(3,5)    # false


(Those two lines are my only tests at the moment so try it out some
more :-)


David

-- 
* Books:
   RAILS ROUTING (new! http://www.awprofessional.com/title/0321509242)
   RUBY FOR RAILS (http://www.manning.com/black)
* Ruby/Rails training
     & consulting:  Ruby Power and Light, LLC (http://www.rubypal.com)