From: Fred Phillips <fophillips1990@...>
Date: 2007-07-29T02:01:04+09:00
Subject: Re: Finding un-escaped characters in scan()

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Excellent, that works like a charm. Thanks.

On 28/07/07, Harry Kakueki <list.push@gmail.com> wrote:
>
> On 7/28/07, Harry Kakueki <list.push@gmail.com> wrote:
> > On 7/28/07, Fred Phillips <fophillips1990@gmail.com> wrote:
> > > I have a string that looks like this: "test,,\,test". And I'm trying
> to
> > > count the commas which don't follow a \. But when using scan(/[^\\],/)
> it
> > > only finds the first comma. I think this is because after scan() has
> found a
> > > comma without a backslash, it continues from where it left off, and
> since
> > > there's no character before the next comma, it won't match it. Does
> anyone
> > > know how to fix it?
> > >
> > Are you expecting something like this,
> >
> > str = "test,,,test"
> > p str.scan(/,,/) #[",,"]
> >
> > to give you [",,",",,"]     ?
> >
> > Harry
>
> If so,
> here is one way.
> There is probably a more elegant way.
>
> require 'enumerator'
> str = "test,,\\,,,\\,,"
> str.split(//).each_cons(2){|x|p x[1] if x[0] != "\\" and x[1] == ","}
>
> Harry
>
> --
> A Look into Japanese Ruby List in English
> http://www.kakueki.com/
>
>

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