From: Phrogz <phrogz@...>
Date: 2007-07-28T07:10:01+09:00
Subject: Re: n00b if condition quest

On Jul 27, 4:43 am, "Robert Dober" <robert.do...@gmail.com> wrote:
> On 7/27/07, dbl...@rubypal.com <dbl...@rubypal.com> wrote:
> > On Fri, 27 Jul 2007, Brett Boge wrote:
> > > if (a = b or a = c or a = d or a = f)
> > You mean == rather than = , but in any case, try this:
> You are right for sure that OP meant ==, but let us answer the
> original question too ;)
>
> a = [b,c,d,e,f].compact.first

Your solution forces the evaluation of b/c/d/e/f, which the OP's does
not (thanks to the miracle of short-circuit boolean evaluation). I
think the 'correct' answer to the typo-incorrect question is:

  if a = (b or c or d or f)

To be super clear: this is only because we're talking about assignment
instead of an actual equality test.