From: Robert Dober <robert.dober@...>
Date: 2007-07-23T18:13:03+09:00
Subject: Re: how to make a[2][3]=4 work?

On 7/23/07, Fsormok Fsormok <fsormok@inbox.ru> wrote:
> > a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}
>
> > irb(main):026:0> require 'ostruct'
> > irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}
>
> >a = {}
> >    ==>{}
> >a[1] = 1
> >    ==>1
> >a[ [2,1] ] = 2
> >    ==>2
> >a[ [2,2,3] ] = 4
> >    ==>4
> >p a
> >{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
> >    ==>nil
>
> Tanks for the replies.
>
> I'm just a little bit confused because in ruby everything is lean and
> clean but when it comes to hashes of hashes it gets kind of complicated.
> For me it looks like ruby has another "concept" of solving such things.
>

Hmm the context of this statement seems not complete in *this* thread,
maybe you could elaborate on this a little bit?
Personally I feel that Ruby's concept of Hashes is clearcut and
exactly the same as in most of its relatives (Perl,Python...).

What exactly would you like to have "simpler"?

Cheers
Robert



--
As simple as possible,
but not simpler.
-- A. Einstein