From: Fsormok Fsormok <fsormok@...>
Date: 2007-07-23T16:15:22+09:00
Subject: Re: how to make a[2][3]=4 work?

> a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

> irb(main):026:0> require 'ostruct'
> irb(main):027:0> int = Hash.new{|h,k| h[k]=OpenStruct.new}

>a = {}
>    ==>{}
>a[1] = 1
>    ==>1
>a[ [2,1] ] = 2
>    ==>2
>a[ [2,2,3] ] = 4
>    ==>4
>p a
>{[2, 2, 3]=>4, [2, 1]=>2, 1=>1}
>    ==>nil

Tanks for the replies.

I'm just a little bit confused because in ruby everything is lean and 
clean but when it comes to hashes of hashes it gets kind of complicated. 
For me it looks like ruby has another "concept" of solving such things.

-fsormok
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