From: Logan Capaldo <logancapaldo@...>
Date: 2007-07-14T07:38:20+09:00
Subject: Re: gets

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On 7/13/07, John Joyce <dangerwillrobinsondanger@gmail.com> wrote:
>
>
> On Jul 13, 2007, at 8:31 AM, Jeffrey Bowen wrote:
>
> > Thanks
> > Sometime I'm just slow.  I tried
> > "test.chomp = gets" but I didn't try "test =
> > gets.chomp".  The error message most likely told me
> > what was wrong.
> >
> > Thanks
> > Jeff
> >
> > --- Jeffrey Bowen <ja_bowen@yahoo.com> wrote:
> >
> >> Of course the code below will not work because gets
> >> is
> >> adding /n to the entry.  I know that chomp will
> >> remove
> >> the /n but is there away to cut the /n without
> >> reassigning test1 to another variable IE test2 =
> >> test1.comp
> >>
> >> print "test1 "
> >> test1 = gets
> >> puts test1.class
> >> if test1 == "1"
> >>         puts "step 1"
> >> else
> >>         puts "step 2"
> >> end
> >>
> >> Thanks
> >> Jeff
> >>
> test.chomp = gets
>
> and
>
> test = gets.chomp
>
> Will give you different results.
> test.chomp will return a chomped value but doesn't permanently chomp
> the value in test
> you would need to do
>
> test.chomp! = gets


You can't do this. (At least not using that syntax). Furthermore it would
not be able to have the desired semantics anyway.

Your choices are
test1 = gets.chomp

OR

test1 = gets
test1 = test1.chomp

OR

test1 = gets
test1.chomp!

OR

test1 = gets.chomp! # will work in this case, not a good idea from a best
practices POV

I mighta missed a variation, but you definitely can't do test1.chomp! =
gets. That's nonsense.

This is the destructive version of chomp, methods ending with !
> usually modify the receiver in place, others usually don't.
> The reason my version doesn't need chomp! is because it takes the
> chomped value of gets and assigns that to test.
>
>
>

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