From: Wyss Clemens <WYS@...>
Date: 2001-11-20T00:09:54+09:00
Subject: [ruby-talk:25844] RE:  HowTo deal with arrays?

if you very often need this, extend the Array class

class Array
  def plus(other)
    return (0...self.length()).map {|i| self[i] + other[i]}
  end
end

a = Array.new(3, 1)
b = Array.new(3, 2)

c = a.plus(b)
p c

Regards
Clemens
> -----Original Message-----
> From: Martin Kahlert [mailto:martin.kahlert@infineon.com]
> Sent: Montag, 19. November 2001 10:42
> To: ruby-talk@ruby-lang.org
> Subject: [ruby-talk:25834] HowTo deal with arrays?
> 
> 
> Hi!
> I want to do something like that:
> 
> a = Array.new(1000000, 1)
> b = Array.new(1000000, 2)
> c = Array.new(1000000)
> 
> for i in 0 ... a.length
>    c[i] = a[i] + b[i] 
> end
> 
> This looks a bit too C-ish for me.
> 
> Should i use
> (0 ... a.length).each {|i| c[i] = a[i] + b[i]}
> or
> a.length.times {|i| c[i] = a[i] + b[i]}
> or
> a.each_index {|i| c[i] = a[i] + b[i]}
> 
> Which is the 'ruby way' of doing that?
> 
> Background: I did some timing and found 
> a.collect! {|x| x+1}
> to be twice as fast as
> for i in 0 ... a.length 
>   a[i] += 1
> end
> 
> -- 
> The early bird catches the worm. If you want something else for       
> breakfast, get up later.
>