From: "baptiste Auguié" <ba208@...>
Date: 2007-07-04T21:48:15+09:00
Subject: simple question on rbgsl vectors

Hi,


I'm trying to do a simple thing : access elements of a vector  
specified by their index. In Matlab/Octave i would do,

newVector=oldVector( [1, 3, 56, 72] )

How does this work with Ruby vectors?

oldVector.get(3,4,5) returns the first 3 elements, where I would  
expect the 2nd, 3d and 4th.

I've had to do a twisted version of this using arrays and lists,

a2=[]
(0..200).step(10) {|i|  a2 << a[i] }

I find it very inefficient and annoying, plus I do need to use  
vectors rather than arrays and lists and do not really know how to  
convert between these three :(


Oh, and just a quick question: how can i do two instructions in one  
block ? I have to repeat the same instructions over and over like  
shown below...

a2=[]
b2=[]
(0..200).step(10) {|i|  a2 << a[i] }
(0..200).step(10) {|i|  b2 << b[i] }

Best regards,

baptiste