From: Robert Dober <robert.dober@...>
Date: 2007-06-30T16:32:51+09:00
Subject: Re: Regular Expression question

On 6/30/07, Peter Seebach <seebs@seebs.net> wrote:
> In message <0df4a451b19810ff6e06f11725324591@ruby-forum.com>, Al Cholic writes:
> >Im working with regular expressions and I cant quite understand how the
> >"13" is extracted from the string.
> >Here is the irb output:
> >irb(main):005:0> "(13)"[1..-2].to_i
> >=> 13
> >I dont understadn how the [1..-2] parameter removes the parenthases from
> >the string.
>
> "(13)"[0] = "("
> "(13)"[1] = "1"
> "(13)"[2] = "3"
> "(13)"[3] = ")"
>
> "(13)"[-1] = ")"
> "(13)"[-2] = "3"
> "(13)"[-3] = "1"
> "(13)"[-4] = "("
Maybe it would not hurt to add a little clarification, albeit the fact
that your didactic simplification has worked very well :). Especially
as this concerns a FAQ

In reality
"(13)"[0] => ?( which equals 40
and
"(13)"[0..0] => "("

Cheers
Robert
-- 
I always knew that one day Smalltalk would replace Java.
I just didn't know it would be called Ruby
-- Kent Beck