From: Al Cholic Date: 2007-06-30T11:50:42+09:00 Subject: Re: Regular Expression question > "(13)"[0] = "(" > "(13)"[1] = "1" > "(13)"[2] = "3" > "(13)"[3] = ")" > > "(13)"[-1] = ")" > "(13)"[-2] = "3" > "(13)"[-3] = "1" > "(13)"[-4] = "(" > > "-N" counts from the end, starting with -1. Thanks. An the .. in [1..-2] means "keep everything in between" ? -- Posted via http://www.ruby-forum.com/.