From: Matt Filizzi <fizz@...>
Date: 2007-06-19T02:19:35+09:00
Subject: Re: Another Easy Beginner Question

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Wouldn't it be this...

gifts = 0
(1..12).each do |x|
  (1..x).each do { |y| gifts += y }
end

puts gifts

Note the difference between mine and yours,  where I count each item instead
of each set.  So 5 gold rings counts as 5 instead of 1.  I think it all
depends on how the original question was intended.

On 6/18/07, Sammy Larbi <sam@powersource.com> wrote:
>
> I'm not sure why you'd want to, but I suppose you could do something like:
>
> gifts=0
> (1..12).each do |i|
>     (1..i).each { |j| gifts += 1 }
> end
> puts gifts
>
> danielj wrote, On 6/18/2007 11:50 AM:
> > There is a song that goes like this:
> >
> >     On the first day of Christmas, my true love sent to me a partridge
> > in a pear tree.
> >     On the second day of Christmas, my true love sent to me two turtle
> > doves and a partridge in a pear tree.
> >     ...
> >
> > If this goes on for the 12 days of Christmas. How many presents will
> > your true love send you over Christmas?
> > <strong>(Hint: You will need a loop inside another). </strong>
> >
> > I don't think you need a loop inside a loop.... Here is what I did:
> >
> > day = 0
> > gifts = 0
> >
> > 12.times do
> >  day = day + 1
> >  gifts = gifts + day
> > end
> >
> > print gifts
> >
> > Does anyone know how you would do it with a <em>loop inside a loop</
> > em>?
> >
> >
> >
> >
> >
>
>
>

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