From: Rob Biedenharn <Rob@...>
Date: 2007-06-18T20:56:16+09:00
Subject: Re: Parsing strings

On Jun 18, 2007, at 4:03 AM, Dan German wrote:
> come wrote:
>> You could try :
>>
>> url='http://www.youtube.com/watch?v=OY8AIhbqPHo'
>> url[/watch\?/]=""
>>
>> or with a postive lookahead : url[/watch\?(?=v=OY8AIhbqPHo)/]=""
>
> Thanks...that last expression worked well but I have one last  
> question:
> I didn't realize this before but I also need to remove the equal sign
> after the v and replace it with a forward slash ('/') so that it looks
> like 'http://www.youtube.com/v/OY8AIhbqPHo'

so just do that:

url.sub(/watch\?v=/, 'v/')

or if the variable wasn't always 'v':

url.sub(/watch\?(.)=/, '\1/')

-Rob

Rob Biedenharn		http://agileconsultingllc.com
Rob@AgileConsultingLLC.com