From: "Eric I." Date: 2007-06-18T04:30:24+09:00 Subject: Re: [SOLUTION] Verbal Arithmetic (#128) This program solves addition problems with any number of terms. It finds and displays all solutions to the problem. The solving process is broken up into a sequence of simple steps all derived from class Step. A Step can be something such as 1) choosing an available digit for a given letter or 2) summing up a column and seeing if the result matches an already-assigned letter. As steps succeed the process continues with the following steps. But if a step fails (i.e., there's a contradiction) then the system backs up to a point where another choice can be made. This is handled by recursing through the sequence of steps. In fact, even when a solution is found, the program still backtracks to find other solutions. The expectation is that by testing for contradictions as early as possible in the process we'll tend to avoid dead ends and the result will be much better than an exhaustive search. For example, here are the steps for a sample equation: send +more ----- money 1. Choose a digit for "d". 2. Choose a digit for "e". 3. Sum the column using letters "d", "e" (and include carry). 4. Set the digit for "y" based on last column summed. 5. Choose a digit for "n". 6. Choose a digit for "r". 7. Sum the column using letters "n", "r" (and include carry). 8. Verify that last column summed matches current digit for "e". 9. Choose a digit for "o". 10. Sum the column using letters "e", "o" (and include carry). 11. Verify that last column summed matches current digit for "n". 12. Choose a digit for "s". 13. Verify that "s" has not been assigned to zero. 14. Choose a digit for "m". 15. Verify that "m" has not been assigned to zero. 16. Sum the column using letters "s", "m" (and include carry). 17. Verify that last column summed matches current digit for "o". 18. Sum the column using letters (and include carry). 19. Verify that last column summed matches current digit for "m". 20. Display a solution (provided carry is zero)! Eric ---- Are you interested in on-site Ruby training that's been highly reviewed by former students? http://LearnRuby.com ==== # This is a solution to Ruby Quiz #128. As input it takes a "word # equation" such as "send+more=money" and determines all possible # mappings of letters to digits that yield a correct result. # # The constraints are: 1) a given digit can only be mapped to a single # letter, 2) the first digit in any term cannot be zero. # # The solving process is broken up into a sequence of simple steps all # derived from class Step. A Step can be something such as 1) # choosing an available digit for a given letter or 2) summing up a # column and seeing if the result matches an already-assigned letter. # As steps succeed the process continues with the following steps. # But if a step fails (i.e., there's a contradiction) then the system # backs up to a point where another choice can be made. This is # handled by recursing through the sequence of steps. In fact, even # when a solution is found, the program still backtracks to find other # solutions. require 'set' # State represents the stage of a partially solved word equation. It # keeps track of what digits letters map to, which digits have not yet # been assigned to letters, and the results of the last summed column, # including the resulting digit and any carry if there is one. class State attr_accessor :sum, :carry attr_reader :letters def initialize() @available_digits = Set.new(0..9) @letters = Hash.new @sum, @carry = 0, 0 end # Return digit for letter. def [](letter) @letters[letter] end # The the digit for a letter. def []=(letter, digit) # if the letter is currently assigned, return its digit to the # available set @available_digits.add @letters[letter] if @letters[letter] @letters[letter] = digit @available_digits.delete digit end # Clear the digit for a letter. def clear(letter) @available_digits.add @letters[letter] @letters[letter] = nil end # Return the available digits as an array copied from the set. def available_digits @available_digits.to_a end # Tests whether a given digit is still available. def available?(digit) @available_digits.member? digit end # Receives the total for a column and keeps track of it as the # summed-to digit and any carry. def column_total=(total) @sum = total % 10 @carry = total / 10 end end # Step is an "abstract" base level class from which all the "concrete" # steps can be deriveds. It simply handles the storage of the next # step in the sequence. Subclasses should provide 1) a to_s method to # describe the step being performed and 2) a perform method to # actually perform the step. class Step attr_writer :next_step end # This step tries assigning each available digit to a given letter and # continuing from there. class ChooseStep < Step def initialize(letter) @letter = letter end def to_s "Choose a digit for \"#{@letter}\"." end def perform(state) state.available_digits.each do |v| state[@letter] = v @next_step.perform(state) end state.clear(@letter) end end # This step sums up the given letters and changes to state to reflect # the sum. Because we may have to backtrack, it stores the previous # saved sum and carry for later restoration. class SumColumnStep < Step def initialize(letters) @letters = letters end def to_s list = @letters.map { |l| "\"#{l}\"" }.join(', ') "Sum the column using letters #{list} (and include carry)." end def perform(state) # save sum and carry saved_sum, saved_carry = state.sum, state.carry state.column_total = state.carry + @letters.inject(0) { |sum, letter| sum + state[letter] } @next_step.perform(state) # restore sum and carry state.sum, state.carry = saved_sum, saved_carry end end # This step determines the digit for a letter given the last column # summed. If the digit is not available, then we cannot continue. class AssignOnSumStep < Step def initialize(letter) @letter = letter end def to_s "Set the digit for \"#{@letter}\" based on last column summed." end def perform(state) if state.available? state.sum state[@letter] = state.sum @next_step.perform(state) state.clear(@letter) end end end # This step will occur after a column is summed, and the result must # match a letter that's already been assigned. class CheckOnSumStep < Step def initialize(letter) @letter = letter end def to_s "Verify that last column summed matches current " + "digit for \"#{@letter}\"." end def perform(state) @next_step.perform(state) if state[@letter] == state.sum end end # This step will occur after a letter is assigned to a digit if the # letter is not allowed to be a zero, because one or more terms begins # with that letter. class CheckNotZeroStep < Step def initialize(letter) @letter = letter end def to_s "Verify that \"#{@letter}\" has not been assigned to zero." end def perform(state) @next_step.perform(state) unless state[@letter] == 0 end end # This step represents finishing the equation. The carry must be zero # for the perform to have found an actual result, so check that and # display a digit -> letter conversion table and dispaly the equation # with the digits substituted in for the letters. class FinishStep < Step def initialize(equation) @equation = equation end def to_s "Display a solution (provided carry is zero)!" end def perform(state) # we're supposedly done, so there can't be anything left in carry return unless state.carry == 0 # display a letter to digit table on a single line table = state.letters.invert puts puts table.keys.sort.map { |k| "#{table[k]}=#{k}" }.join(' ') # display the equation with digits substituted for the letters equation = @equation.dup state.letters.each { |k, v| equation.gsub!(k, v.to_s) } puts puts equation end end # Do a basic test for the command-line arguments validity. unless ARGV[0] =~ Regexp.new('^[a-z]+(\+[a-z]+)*=[a-z]+$') STDERR.puts "invalid argument" exit 1 end # Split the command-line argument into terms and figure out how many # columns we're dealing with. terms = ARGV[0].split(/\+|=/) column_count = terms.map { |e| e.size }.max # Build the display of the equation a line at a time. The line # containing the final term of the sum has to have room for the plus # sign. display_columns = [column_count, terms[-2].size + 1].max display = [] terms[0..-3].each do |term| display << term.rjust(display_columns) end display << "+" + terms[-2].rjust(display_columns - 1) display << "-" * display_columns display << terms[-1].rjust(display_columns) display = display.join("\n") puts display # AssignOnSumStep which letters cannot be zero since they're the first # letter of a term. nonzero_letters = Set.new terms.each { |e| nonzero_letters.add(e[0, 1]) } # A place to keep track of which letters have so-far been assigned. chosen_letters = Set.new # Build up the steps needed to solve the equation. steps = [] column_count.times do |column| index = -column - 1 letters = [] # letters for this column to be added terms[0..-2].each do |term| # for each term that's being added... letter = term[index, 1] next if letter.nil? # skip term if no letter in column letters << letter # note that this letter is part of sum # if the letter does not have a digit, create a ChooseStep unless chosen_letters.member? letter steps << ChooseStep.new(letter) chosen_letters.add(letter) steps << CheckNotZeroStep.new(letter) if nonzero_letters.member? letter end end # create a SumColumnStep for the column steps << SumColumnStep.new(letters) summed_letter = terms[-1][index, 1] # the letter being summed to # check whether the summed to letter should already have a digit if chosen_letters.member? summed_letter # should already have a digit, check that summed digit matches it steps << CheckOnSumStep.new(summed_letter) else # doesn't already have digit, so create a AssignOnSumStep for # letter steps << AssignOnSumStep.new(summed_letter) chosen_letters.add(summed_letter) # check whether this letter cannot be zero and if so add a # CheckNotZeroStep steps << CheckNotZeroStep.new(summed_letter) if nonzero_letters.member? summed_letter end end # should be done, so add a FinishStep steps << FinishStep.new(display) # print out all the steps # steps.each_with_index { |step, i| puts "#{i + 1}. #{step}" } # let each step know about the one that follows it. steps.each_with_index { |step, i| step.next_step = steps[i + 1] } # start performing with the first step. steps.first.perform(State.new)