From: Daniel Martin <martin@...>
Date: 2007-06-12T21:21:06+09:00
Subject: Re: how to make a[2][2][3]=4 work?

In addition to what's already been posted, there's this, which doesn't
require any extra variables or methods:

a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}

gz zz <gpygood@126.com> writes:

> a[2][1]=2
> a[2][2][3]=4
> a[3][1][1][1]=1
> p a

irb(main):001:0> a = Hash.new{|h,k| h[k]=Hash.new &h.default_proc}
=> {}
irb(main):002:0> a[2][1]=2
=> 2
irb(main):003:0> a[2][2][3]=4
=> 4
irb(main):004:0> a[3][1][1][1]=1
=> 1
irb(main):005:0> p a
{2=>{1=>2, 2=>{3=>4}}, 3=>{1=>{1=>{1=>1}}}}
=> nil


-- 
s=%q(  Daniel Martin -- martin@snowplow.org
       puts "s=%q(#{s})",s.to_a.last       )
       puts "s=%q(#{s})",s.to_a.last