From: "Federico Zagarzazú" <fzagarzazu@...>
Date: 2007-06-07T14:56:53+09:00
Subject: Re: Error when substituting a backslash in a string

Thanks for the link, it cleared my doubts.

On 6/7/07, james.d.masters@gmail.com <james.d.masters@gmail.com> wrote:
> On Jun 6, 4:27 pm, "Federico Zagarzaz�" <fzagarz...@gmail.com> wrote:
> > 1) puts 'fede'.sub('e', '\4')     # => fde
> > 2) puts 'fede'.sub('e', '\\4')    # => fde
> > 3) puts 'fede'.sub('e', '\\\4')   # => f\4de
> > 4) puts 'fede'.sub('e', '\\\\4')  # => f\4de
> > 5) puts 'fede'.sub('e', '\\\\\4') # => f\de
> > 6) puts 'fede'.sub('e', '\\\\\\4') # => f\de
> > 7) puts 'fede'.sub('e', '\\\\\\\4') # => f\\4de
>
> You have to be careful with using backslashes with a number for a
> replacement string.  In a replacement string, \# (where # is a number)
> indicates that you want to insert something that was matched in the
> original string - the matched things are in parentheses and occur in
> regular expressions.  For example:
>
> irb(main):001:0> a = "Page 3 of 86"
> => "Page 3 of 86"
> irb(main):002:0> a.sub(/^Page (\d+) of (\d+)$/, 'You are on page \1
> out of a total of \2 pages')
> => "You are on page 3 out of a total of 86 pages"
>
> The PickAxe has an excellent subject on this and goes over your
> question with all sorts of backslash permutations.  I guarantee that
> it will clarify things further for you:
>
> http://www.rubycentral.com/book/tut_stdtypes.html
> (see "Backslash Sequences in the Substitution" section)
>
>
>