From: gga <GGarramuno@...>
Date: 2007-06-05T13:55:04+09:00
Subject: Re: Ruby problem with conditional ranges

On Jun 4, 9:51 pm, "Todd A. Jacobs" <tjacobs-
sndr-019...@codegnome.org> wrote:
> On Mon, Jun 04, 2007 at 04:35:25PM +0900, come wrote:
>
> prints up to "four" when (as I understand it) it should stop at "three"
> since "## four" would make the if-statement false. Am I still missing
> something obvious?
>

Yes.  That will never work, as this is not Perl nor are you creating a
range of regexp (which cannot be done, btw).
See what happens when the match does happen as you want:

irb> a = 'four'
irb> (a =~ /two/)...(a =~ /four/)
ArgumentError: bad value for range

[result is:  (nil...'four') ]

Plus the uncommented # in the regex are probably making ruby assume a
comment.

This is another way of writing what you want to do:

#!/usr/bin/ruby -w

## one
## two
## three
## four
## five


File.open($0) do |file|
  range = [ '$_ =~ /^## two/', '$_ !~ /^## four/' ]
  while file.gets
    if eval("#{range[0]}")
      print $_.sub(/^## /, '');
      range.shift
    end
  end
end