From: david karapetyan <dkarapetyan@...>
Date: 2007-06-04T13:25:50+09:00
Subject: Re: code problems

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thanks. i didn't realize i had to provide the block as well when i was
creating the closure. i was hoping for a closure that could take a different
block every time. i wanted fib to be a function that had access to a and b
and every call to fib would require a block. as it is fib has its block
fixed at creation time. do you know of a way of doing what i wanted to do
originally?

On 6/3/07, Nobuyoshi Nakada <nobu@ruby-lang.org> wrote:
>
> Hi,
>
> At Mon, 4 Jun 2007 12:36:50 +0900,
> david karapetyan wrote in [ruby-talk:254217]:
> > why is the following code not valid
>
> It is valid.
>
> > def fibber
> >     a = 1
> >     b = 1
> >     lambda do
> >         yield(a)
> >         a,b = a+b,a
> >     end
> > end
>
> irb(main):009:0> fib = fibber{|x|p x}
> => #<Proc:0xb7c63a74@(irb):4>
> irb(main):010:0> fib[]
> 1
> => [2, 1]
> irb(main):011:0> fib[]
> 2
> => [3, 2]
> irb(main):012:0> fib[]
> 3
> => [5, 3]
>
> --
> Nobu Nakada
>
>

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