From: Enrique Comba Riepenhausen <ecomba@...>
Date: 2007-05-26T05:49:48+09:00
Subject: Re: printing nil objects

On 25 May 2007, at 22:40, finer recliner wrote:

> On May 25, 4:31 pm, Enrique Comba Riepenhausen <eco...@mac.com> wrote:
>>> ### code starts here ###
>>> c1 = Node.new(1,nil,nil)
>>> c2 = Node.new(2,nil,nil)
>>> c3 = Node.new(3,nil,nil)
>>
>>> c1.setP1(c2)
>>> c1.setP2(c2)
>>> c2.setP1(c3)
>>
>>> current = c1
>>> while current.getP1 != nil
>>>     print "value = #{current.getV}, pointer1 = # 
>>> {current.getP1.getV},
>>> "
>>>     if current.getP2.getV != nil then print "pointer2 =
>>> #{current.getP2.getV}\n" else print "null\n" end
>>>     current = current.getP1
>>> end
>>> [/code]
>>
>> Your problem lies exactly there. You are trying to make a method call
>> (getV) on a nil object, and obviously it doesn't have the (getV)
>> method...
>>
>> Try the following
>>
>> if current.getP2.nil? then....
>>
>> That should work.
>>
>> Cheers,
>>
>> ----
>> Enrique Comba Riepenhausen
>> eco...@mac.com
>>
>> I always thought Smalltalk would beat Java, I just didn't know it
>> would be called 'Ruby' when it did.
>> -- Kent Beck
>
> ooooh. now i feel foolish lol. thanks!

Why should you? No one is perfect and sometimes when in the middle of  
the brain crunching activity we oversee the simplest things... :)

Cheers,

----
Enrique Comba Riepenhausen
ecomba@mac.com

I always thought Smalltalk would beat Java, I just didn't know it  
would be called 'Ruby' when it did.
-- Kent Beck