From: finer recliner Date: 2007-05-26T05:40:03+09:00 Subject: Re: printing nil objects On May 25, 4:31 pm, Enrique Comba Riepenhausen wrote: > > ### code starts here ### > > c1 = Node.new(1,nil,nil) > > c2 = Node.new(2,nil,nil) > > c3 = Node.new(3,nil,nil) > > > c1.setP1(c2) > > c1.setP2(c2) > > c2.setP1(c3) > > > current = c1 > > while current.getP1 != nil > > print "value = #{current.getV}, pointer1 = #{current.getP1.getV}, > > " > > if current.getP2.getV != nil then print "pointer2 = > > #{current.getP2.getV}\n" else print "null\n" end > > current = current.getP1 > > end > > [/code] > > Your problem lies exactly there. You are trying to make a method call > (getV) on a nil object, and obviously it doesn't have the (getV) > method... > > Try the following > > if current.getP2.nil? then.... > > That should work. > > Cheers, > > ---- > Enrique Comba Riepenhausen > eco...@mac.com > > I always thought Smalltalk would beat Java, I just didn't know it > would be called 'Ruby' when it did. > -- Kent Beck ooooh. now i feel foolish lol. thanks!