From: Ruby Quiz Date: 2007-05-17T20:59:20+09:00 Subject: [SUMMARY] Huffman Encoder (#123) With the extra credits, this problem is a little involved and some people did write a lot of code for it. Building the tree was our main interest in this problem though. The quiz didn't detail that process too much, but several submitters found write-ups like the one at Wikipedia. The trick is generally to use two queues. The first starts with all of the letters queued lowest frequency to the highest and the second starts empty. While there is more than one node in the combined queues, you dequeue the two with the lowest weights, build a new node with them as children and a combined weight, then enqueue that in the second queue. When you get down to just one node, you are finished. That single node is the root of the tree. A variation on this strategy is to use a single priority queue. When working this way you can always just pull the two lowest entries, since the queue will keep them coming in the proper order. Drew Olson has some pretty easy to follow code using the priority queue approach, so let's look into that now. First, Drew had to build a priority queue since one doesn't ship with Ruby: # priority queue for nodes class NodeQueue def initialize @queue = [] end def enqueue node @queue << node @queue = @queue.sort_by{|x|[-x.weight,x.val.size]} end def dequeue @queue.pop end def size @queue.size end end This is a trivial implementation that just resorts the queue after each new entry. Note that the sort is on the opposite of the weights to put the lowest entries at the front. This is not ideal, of course, but likely to be reasonably quick if you are just encoding simple text. That's because the sort is largely in C. For a better priority queue, have a peek at Daniel Martin's code. Drew also used a trivial class to represent nodes in the tree: # class to hold nodes in the huffman tree class Node attr_accessor :val,:weight,:left,:right def initialize(val="",weight=0) @val,@weight = val,weight end def children? return @left || @right end end As you can see, Nodes are pretty much just a Struct for tracking value, weight, and children. The additional method just checks to see if this node is a branch, meaning that it has at least one child node. With those tools to build on, Drew is now ready to create a HuffmanTree: # HuffmanTree represents the tree with which we perform # the encoding class HuffmanTree # initialize the tree based on data def initialize data @freqs = build_frequencies(data) @root = build_tree end #encode the given data def encode data data.downcase.split(//).inject("") do |code,char| code + encode_char(char) end end def decode data node = @root if !@root.children? return @root.val end data.split(//).inject("") do |phrase,digit| if digit == "0" node = node.left else node = node.right end if !node.children? phrase += node.val node = @root end phrase end end # ... These three methods define the external interface for this class. First, you create HuffmanTree objects by passing in the data a tree should be constructed from. Frequencies are counted for the characters in the data and a tree is built from those counts. The encode() method takes the data you wish to apply the encoding to and returns a String of ones and zeros representing the data. This implementation just iterates over the characters, using a helper method to translate them. Note that Drew's implementation normalizes case which results in smaller encodings, but this step needs to be removed if you want lossless compression. The decode method is the most complex in the set, but still not too hard to grasp. It starts at the root node and iterates over each one and zero, selecting the correct child node. Each time it reaches a leaf node (no children), that character value is added to the translation and the search resets to the root node. Now we just need to see the helper methods used in those methods. This first one is the reverse of the decoder we just examined: # ... private # this method encodes a given character based on our # tree representation def encode_char char node = @root coding = "" # encode to 0 if only one character if !@root.children? return "0" end # we do a binary search, building the representation # of the character based on which branch we follow while node.val != char if node.right.val.include? char node = node.right coding += "1" else node = node.left coding += "0" end end coding end # ... Again, the search begins with the root node and advances down the tree branches. This time the search is for nodes containing the character and we can stop as soon as we reach a leaf. The encoding is the path of one and zero branches that lead to the character. These last two methods handle tree construction: # ... # get word frequencies in a given phrase def build_frequencies phrase phrase.downcase.split(//).inject(Hash.new(0)) do |hash,item| hash[item] += 1 hash end end # build huffmantree using the priority queue method def build_tree queue = NodeQueue.new # build a node for each character and place in pqueue @freqs.keys.each do |char| queue.enqueue(Node.new(char,@freqs[char])) end while !queue.size.zero? # if only one node exists, it is the root. return it return queue.dequeue if queue.size == 1 # dequeue two lightest nodes, create parent, # add children and enqueue newly created node node = Node.new node.right = queue.dequeue node.left = queue.dequeue node.val = node.left.val+node.right.val node.weight = node.left.weight+node.right.weight queue.enqueue node end end end The first method, build_frequencies(), is just a character counter. The counts are returned in a Hash keyed by the character for a given count. The main work is done in build_tree(). It begins by creating a priority queue and queuing each of the characters from the frequency count. After that, the while loop is a direct translation of the process I described at the beginning of this summary. The final bit of code puts the tree to work creating Drew's solution: # get command lines args, build tree and encode data if __FILE__ == $0 require 'enumerator' data = ARGV.join(" ") tree = HuffmanTree.new data # get encoded data and split into bits code = tree.encode(data) encoded_bits = code.scan(/\d{1,8}/) # output puts puts "Original" puts data puts "#{data.size} bytes" puts puts "Encoded" encoded_bits.each_slice(5) do |slice| puts slice.join(" ") end puts "#{encoded_bits.size} bytes" puts puts "%d percent compression" % (100.0 - (encoded_bits.size.to_f/data.size.to_f)*100.0) puts puts "Decoded" puts tree.decode(code) end The first few chunks of this code just run the interface methods we have been examining. The last big chunk is simply the output of results using some straightforward printing logic. My thanks to all who took on this challenge. Several of you wrote library quality solutions. It was impressive to see. Tomorrow we will try some magical math, as quick as we can...