From: Kevin Compton <klcompt@...>
Date: 2007-05-12T01:06:17+09:00
Subject: Re: how to remove dups from 2 lists?

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Looks good to me!

each_item should read each_index
and (perhaps) remove nil check and we're off.



On 5/11/07, Mike Steiner <mikejaysteiner@gmail.com> wrote:
>
> Wow - this question generated lots of replies! I'm still reading through
> all
> of them.
>
> I have another idea, but not sure if this will work:
>
> def RemoveDupsFromLists ( list1 , list2 )
>     list1.each_item do | i |
>         list2.each_item do | j |
>             if !(list2[j].nil?) and list1[i] == list2[j]
>                 list1[i] = nil
>                 list2[j] = nil
>             end
>         end
>     end
>     list1.compact!
>     list2.compact!
>     return [ list1 , list2 ]
> end
>
>
> On 5/11/07, Lloyd Linklater <lloyd@2live4.com> wrote:
> >
> > Harry Kakueki wrote:
> >
> > > What happens here? :)
> > > All 5's are deleted.
> >
> > If you are asking about my example, there were no 5s in it to begin
> > with.  As was observed earlier, I think that better examples would have
> > resulted in better code.  I was mostly interested in finding a rubyish
> > way to make it happen with great simplicity.  If there is something
> > slightly different needed, perhaps a tweak or two to the arrays before
> > applying the differences could handle it.
> >
> > Anyway, this is my first attempt at writing code to solve a question in
> > here.  I am happy that I was able to come up with something that worked
> > and post it.  :)
> >
> > yay ruby!
> >
> > --
> > Posted via http://www.ruby-forum.com/.
> >
> >
>

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