From: SonOfLilit <sonoflilit@...>
Date: 2007-05-11T21:48:39+09:00
Subject: Re: how to remove dups from 2 lists?

I envision using sets:

a = [a, b, c, d, e, e]
b = [d, e, f, f, g]
dups = a.to_set & b

a -= dups # => [a, b, c]
b -= dups # => [f, f, g]

Or how about just using #-?

a = [a, b, c, d, e, e]
b = [d, e, f, f, g]
c = a.dup
d = b.dup

b -= c # => [a, b, c]
a -= d # => [f, f, g]

Do these fit?

Aur

P.S. have you had a look at http://RubyMentor.rubyforge.org/

On 5/11/07, Kevin Compton <klcompt@gmail.com> wrote:
> Assuming my previous assumption of what exactly is needed... at this point
> it's academic anyway, right :>
>
> This will produce the same result with much cleaner code than my previous
> post:
>
>
> APPENDAGE_START = "_"
>
> def make_items_unique(list)
>   hsh = Hash.new { |h,k| h[k] = 0}
>   list_mod = list.collect do |x|
>     hsh[x] += 1
>     x.to_s + APPENDAGE_START + hsh[x].to_s
>   end
> end
>
> list1 = %w{one one two three four four five}
> list2 = %w{one three three four five five five}
>
> puts "before --- list1:#{list1}"
> puts "before --- list2:#{list2}"
>
> list1_mod = make_items_unique(list1)
> list2_mod = make_items_unique(list2)
>
> list3 = list1_mod - list2_mod
> list4 = list2_mod - list1_mod
>
> list1 = list3.collect { |x| x.split(APPENDAGE_START)[0] }
> list2 = list4.collect { |x| x.split(APPENDAGE_START)[0] }
>
> puts "after --- list1:#{list1}"
> puts "after --- list2:#{list2}"
>
> ---------------
> output=
> before --- list1:oneonetwothreefourfourfive
> before --- list2:onethreethreefourfivefivefive
> after --- list1:onetwofour
> after --- list2:threefivefive
>
>
> On 5/11/07, Enrique Comba Riepenhausen <ecomba@mac.com> wrote:
> >
> >
> > On 11 May 2007, at 10:23, Brian Candler wrote:
> >
> > > On Fri, May 11, 2007 at 04:55:14PM +0900, Enrique Comba
> > > Riepenhausen wrote:
> > >> Do you want to remove the elements that are in the same position on
> > >> the lists and are equal?
> > >>
> > >> If so I would say:
> > >>
> > >> require 'generator'
> > >>
> > >> list1 = [1,1,2,3,4,6] # => I included the 6 to show what I mean...
> > >> list2 = [2,2,3,5,5,6] # => I included the 6 to show what I mean...
> > >>
> > >> def RemoveDupsFromLists ( list1 , list2 )
> > >>   lists = SyncEnumerator.new(list1, list2)
> > >>   lists.each { |element_list1, element_list2|
> > >>
> > >>     if list1[element_list1] == list2[element_list2]
> > >>       list1.delete(element_list1)
> > >>       list2.delete(element_list2)
> > >>     end
> > >>   }
> > >> end
> > >
> > > Is it safe to delete from lists while you're enumerating through them?
> >
> > Actually not ;) It depends if other objects are trying to access
> > those lists at the same time though...
> >
> >
> >
>