From: Rick DeNatale <rick.denatale@...>
Date: 2007-05-11T03:20:37+09:00
Subject: Re: What's the most ruby-ish way to write this python code?

On 5/10/07, Robert Klemme <shortcutter@googlemail.com> wrote:
> On 09.05.2007 21:02, Drew Olson wrote:

Here's another way to do it:

letters = ('a'..'z').to_a
word = 'word'

ans = []
(0..word.size).each do |i|
  letters.each do |c|
    ans << word.sub(/.{#{i}}/, "\\0#{c}")
  end
end

print ans.join("\n")

or as an enumerator:

class Wordgen
  include Enumerable

  attr_accessor :word

  Letters = ('a'..'z').to_a

  def initialize(word)
    self.word = word
  end

  def each
    (0..word.size).each do |i|
      Letters.each do |c|
	yield word.sub(/.{#{i}}/, "\\0#{c}")
      end
    end
  end
end

Wordgen.new("word").each do |ans|
  p ans
end



-- 
Rick DeNatale

My blog on Ruby
http://talklikeaduck.denhaven2.com/