From: Jason Roelofs <jameskilton@...>
Date: 2007-05-10T21:48:20+09:00
Subject: Re: loop questions

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i.times do |x|
  puts x
end

You have to specify what the internal variable is.

As for the pascal code:

5.downto(1) do |x|
  puts x
end

Here are a few links to help out with these types of questions:

Ruby Core API: http://ruby-doc.org/core/
Ruby Stdlib API: http://ruby-doc.org/stdlib

Pragmatic Programmers Guide: http://www.rubycentral.com/book/

_why's poignant guide to Ruby (this one is odd):
http://poignantguide.net/ruby/

Jason

On 5/10/07, Lloyd Linklater <lloyd@2live4.com> wrote:
>
> I am new to ruby and loving it so far and have beginner's questions
> about loops.
>
> I wanted something like this:
>
> for (int i = 1; i <= 5; i++)
>   printf("%d\n", [i]);
>
> expecting:
>
> 1
> 2
> 3
> 4
> 5
>
>
> I wrote this:
>
> i = 5
>
> i.times do
>   puts i.to_s
> end
>
> And got:
>
> 5
> 5
> 5
> 5
> 5
>
> I am guessing that there is an internal variable that is incremented.
> doh!  Is there a way to get the changing variable in there without
> having a separate variable in there?
>
> Anyway, I then tried this:
>
> for i in 1..5
>   puts i.to_s
> end
>
> Which worked as expected.  But I had better use for a descending loop.
> In pascal it would be
>
> for i := 5 downto 1 do
>   writeln('%d', [i]);
>
> but I could not figure out how to do that in a for loop.  I looked
> through several books and could not find the answer.  Any tips?
>
> --
> Posted via http://www.ruby-forum.com/.
>
>

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