From: Niko <niko@...>
Date: 2007-05-10T21:47:20+09:00
Subject: Re: loop questions


Hi

5.times do |i|
  puts i
end

0
1
2
3
4

1.upto(5) do |i|
  puts i
end

1
2
3
4
5

5.downto(1) do |i|
  puts i
end

5
4
3
2
1


Lloyd Linklater wrote:
> I am new to ruby and loving it so far and have beginner's questions
> about loops.
>
> I wanted something like this:
>
> for (int i = 1; i <= 5; i++)
>   printf("%d\n", [i]);
>
> expecting:
>
> 1
> 2
> 3
> 4
> 5
>
>
> I wrote this:
>
> i = 5
>
> i.times do
>   puts i.to_s
> end
>
> And got:
>
> 5
> 5
> 5
> 5
> 5
>
> I am guessing that there is an internal variable that is incremented.
> doh!  Is there a way to get the changing variable in there without
> having a separate variable in there?
>
>   
> Anyway, I then tried this:
>
> for i in 1..5
>   puts i.to_s
> end
>
> Which worked as expected.  But I had better use for a descending loop.
> In pascal it would be
>
> for i := 5 downto 1 do
>   writeln('%d', [i]);
>
> but I could not figure out how to do that in a for loop.  I looked
> through several books and could not find the answer.  Any tips?
>
>