From: Nanyang Zhan <sxain@...>
Date: 2007-05-07T21:22:35+09:00
Subject: Re: separate Chinese and English! with Ruby

Harry Kakueki wrote:
> On 5/7/07, Nanyang Zhan <sxain@hotmail.com> wrote:
>>
>>
> Try something like this.
> 
> t = str.split(//).partition {|x| x=~/[a-z]|[A-Z]/ }
> p t[0].join
> p t[1].join
> 
> Harry
Thanks, KaKuEKi, but:
!!!!below code were tested under Ruby on Rails console!!!
>> str1 = "中文 English Words"
=> "中文 English Words"
>> str2 = "Ôkami: chi"
=> "Ôkami: chi"
>> t = str2.split(//).partition { |x| x=~/[a-z]|[A-Z]/}
=> [["k", "a", "m", "i", "c", "h", "i"], ["Ô", ":", " "]]
>> p t[0].join
"kamichi"  ##########I want all non Chinese characters remained.
=> nil
>> t = str1.split(//).partition { |x| x=~/[a-z]|[A-Z]/}
=> [["E", "n", "g", "l", "i", "s", "h", "W", "o", "r", "d", "s"], ["中", 
"文", " ", " "]]
>> p t[0].join
"EnglishWords"  #######no space
=> nil
>>

Harry Kakueki wrote:

> Or this
> 
> str.split(//).partition {|x| x.length == 1 }
> 
> Harry

this time spaces are kept:
>> t = str1.split(//).partition {|x| x.length == 1 }
=> [[" ", "E", "n", "g", "l", "i", "s", "h", " ", "W", "o", "r", "d", 
"s"], ["中", "文"]]
>> t[0].join
=> " English Words"
>> t = str2.split(//).partition {|x| x.length == 1 }
=> [["k", "a", "m", "i", ":", " ", "c", "h", "i"], ["Ô"]]
>> t[0].join
=> "kami: chi"

I think "Ô" may just like Chinese characters, so it is hard to take it 
out.






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