From: Harry Kakueki <list.push@...>
Date: 2007-05-04T10:17:05+09:00
Subject: Re: Is there a better way to do this?

On 5/4/07, Michael W. Ryder <_mwryder@worldnet.att.net> wrote:
> As part of my learning Ruby I am trying to learn how to format strings.
>   The following is an example for formatting a U.S. phone number:
>
> a = "1234567890"
> b = "(000) 000-0000"
> ai = 0
>
> for i in 0..(b.length) -1
>    if b[i,1] == "0"
>      b[i,1] = a[ai,1]
>      ai += 1
>    end
> end
> puts b
>
> Is there a better (more Rubyish) way to do this?
> Obviously I will want to add more code in the future to handle
> exceptions like phone numbers that are not 10 characters long or are
> longer, but this will get me started.
>
>
I'm sure there are better ways but here is something to look at.

a = "1234567890"
area = a.slice(0..2)
exc = a.slice(3..5)
num = a.slice(6..9)
tel = "(#{area}) #{exc}-#{num}"

p tel

Harry


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