From: Robert Klemme <shortcutter@...>
Date: 2007-05-03T18:00:16+09:00
Subject: Re: It doesn't produce any output!

On 03.05.2007 09:18, Yusuf Celik wrote:
> Thanks Robert,
> 
> But, without #{ObjectSpace._id2ref(id)}  no problem.
> You think this statement locks the object in memory.

No, that's not the one.  The mere fact that you define a proc / lambda 
in the presence of a local variable that references the object is 
keeping the object around.  The proc is a closure and keeps a reference 
to a even if a goes out of scope (which it does not in your case).

	robert